[JEE Advanced 2014] a quadratic p x 0 with real coefficients has purely imaginary roots then p
A quadratic $p(x)=0$ with real coefficients has purely imaginary roots. Then $p(p(x))=0$ has
(a) one purely imaginary root
(b) all real roots
(c) two real and two purely imaginary roots
(d) neither real nor purely imaginary roots
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
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Correct answer: (d) neither real nor purely imaginary roots
$p(x)=a(x^2+k^2)$; $p(p(x))=0\Rightarrow p(x)=\pm ik\Rightarrow x^2=-k^2\pm ik/a$, which is complex but neither real nor purely imaginary.
JEE Advanced 2014 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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