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[JEE Advanced 2005] a square circumscribes the circle z 1 sqrt 2 if one vertex is 2

VAVidaara Admin Asked 2d ago 0 views 1 answer

A square circumscribes the circle $|z-1|=\sqrt2$. If one vertex is $2+\sqrt3\,i$, find the other vertices.

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Answer: $(1-\sqrt3)+i,\quad -\sqrt3\,i,\quad (1+\sqrt3)-i$.

Vertices lie at distance $2$ from the centre $1$; $(2+\sqrt3i)-1=1+\sqrt3i=2e^{i\pi/3}$. Rotating by $\frac\pi2,\pi,\frac{3\pi}2$ about the centre gives $1-\sqrt3+i,\ -\sqrt3 i,\ 1+\sqrt3-i$.

JEE Advanced 2005 · Complex Numbers — verified solution by the Vidaara Team.

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