JEE physics

A thin ring of radius R has charge +Q uniformly distributed — JEE Physics

CChloeLefevre13 Asked 1mo ago 1,044 views 1 answer

A thin ring of radius $R$ has charge $+Q$ uniformly distributed. A particle of mass $m$ and charge $+q$ is placed at the center. It is displaced slightly along the axis. Show it executes SHM and find the time period.

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 8

For displacement $x \ll R$, the restoring force from the ring's field:

$$F = -qE = -\frac{qQx}{4\pi\epsilon_0 R^3}$$

Comparing with $F = -kx$, we get $k = \dfrac{qQ}{4\pi\epsilon_0 R^3}$

$$T = 2\pi\sqrt{\frac{m}{k}} = 2\pi\sqrt{\frac{4\pi\epsilon_0 m R^3}{qQ}}$$

$$T = 2\pi\sqrt{\frac{4\pi\epsilon_0 m R^3}{qQ}}$$

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Discussion (2)

N
Thanks a ton, I was stuck on this exact problem for an hour.
NimalPerera82 · 1mo ago
DM
Is there a faster shortcut for this in the actual exam? Time is tight.
Divya Mehta · 1mo ago
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