If $f(x) = {x^2}\sin \frac{1}{x},$ where $x \ne 0,$ then the value of the function $f$ at $x = 0,$ so that the function is continuous at $x = 0,$ is
If $f(x) = {x^2}\sin \frac{1}{x},$ where $x \ne 0,$ then the value of the function $f$ at $x = 0,$ so that the function is continuous at $x = 0,$ is
Official Solution
VVidaara Team
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$f(x) = {x^2}\sin \left( {\frac{1}{x}} \right)$, where $x \ne 0$
Hence, value of the function $f$ at $x = 0$, so that it is continuous at $x = 0$ is 0 .
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