Continuity and Differentiability — Class 12 Maths Solution

exemplar objective MCQ NCERT Exemp. Ex.5.3 ,Q.88,Page 114

Question

If $f(x) = {x^2}\sin \frac{1}{x},$ where $x \ne 0,$ then the value of the function $f$ at $x = 0,$ so that the function is continuous at $x = 0,$ is

(a) 0 ✓ Correct
(b) -1
(c) 1
(d) None of these

Step-by-step Solution

$f(x) = {x^2}\sin \left( {\frac{1}{x}} \right)$, where $x \ne 0$
Hence, value of the function $f$ at $x = 0$, so that it is continuous at $x = 0$ is 0 .

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NCERT & Exemplar solution for CBSE Class 12 Mathematics, Continuity and Differentiability. Curated by Sachin Sharma. Free for all students.