2x + 3y $=$ sinx

We are given that, 2x + 3y $=$ sin x ...(i)
Differentiating (i) on both sides w.r.t. x, we get
$2 + 3\cfrac{{dy}}{{dx}} = \cos x \Rightarrow \cfrac{{dy}}{{dx}} = \cfrac{{\cos x - 2}}{3}$