2x + 3y $=$ sin y

We are given that, 2x + 3y $=$ sin y ...(i)
Differentiating (i) on both sides w.r.t. x, we get

$2 + 3\cfrac{{dy}}{{dx}} = \cos y\cfrac{{dy}}{{dx}}$

$\Rightarrow$ $\cos y\cfrac{{dy}}{{dx}} - 3\cfrac{{dy}}{{dx}} = 2 \Rightarrow \cfrac{{dy}}{{dx}} = \cfrac{2}{{\cos y - 3}}$