The degree of differential equation $\frac{{{d^2}y}}{{d{x^2}}} + {\left( {\frac{{dy}}{{dx}}} \right)^3} + 6{y^5} = 0$ is
The degree of differential equation $\frac{{{d^2}y}}{{d{x^2}}} + {\left( {\frac{{dy}}{{dx}}} \right)^3} + 6{y^5} = 0$ is
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$\frac{{{d^2}y}}{{d{x^2}}} + {\left( {\frac{{dy}}{{dx}}} \right)^3} + 6{y^5} = 0$
We know that, the degree of a differential equation is exponent heighest of order derivative.
$\therefore$ Degree $= 1$
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