The order and degree of differential equation
${\left( {\frac{{{d^3}y}}{{d{x^3}}}} \right)^2} - 3\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^4} = {y^4}$ are
The order and degree of differential equation
${\left( {\frac{{{d^3}y}}{{d{x^3}}}} \right)^2} - 3\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^4} = {y^4}$ are
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Given that,
${\left( {\frac{{{d^3}y}}{{d{x^3}}}} \right)^2} - 3\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^4} = {y^4}$
$\therefore \quad$
Order $= 3$
and degree $= 2$
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