The order and degree of differential equation
$\left[ {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right] = \frac{{{d^2}y}}{{d{x^2}}}$ are
The order and degree of differential equation
$\left[ {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right] = \frac{{{d^2}y}}{{d{x^2}}}$ are
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Given that, $\left[ {1 + {{\left( {\frac{{dy}}{{dx}}} \right)}^2}} \right] = \frac{{{d^2}y}}{{d{x^2}}}$
$\therefore$ Order $= 2$ and degree $= 1$
Community Answers (0)
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.