The degree of the differential equation ( y d x 2 ) 3 + ( dx ) + ( dx ) + 1 = 0 is 3 2 1 not defined

Option d is correct Since the given differential is not a polynomial in dx , therefore, its degree is not defined.

class 12 maths differential equations

The degree of the differential equation
${\left( {\cfrac{{{d^2}y}}{{d{x^2}}}} \right)^3} + \left( {\cfrac{{dy}}{{dx}}} \right) + \sin \left( {\cfrac{{dy}}{{dx}}} \right) + 1 = 0$ is
• $3$
• $2$
• $1$
• not defined

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#Differential Equations #NCERT #SA #Class 12 Maths

📘 Differential Equations NCERT Ex.9.1,Q.11,Page 383 SA

The degree of the differential equation
${\left( {\cfrac{{{d^2}y}}{{d{x^2}}}} \right)^3} + \left( {\cfrac{{dy}}{{dx}}} \right) + \sin \left( {\cfrac{{dy}}{{dx}}} \right) + 1 = 0$ is

• $3$

• $2$

• $1$

• not defined

Official Solution

VVidaara Team ✓ Verified solution NCERT & Exemplar

Option d is correct

Since the given differential is not a polynomial in $\cfrac{{dy}}{{dx}}$, therefore,

its degree is not
defined.

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The degree of the differential equation ${\left( {\cfrac{{{d^2}y}}{{d{x^2}}}} \right)^3} + \left( {\cfrac{{dy}}{{dx}}} \right) + \sin \left( {\cfrac{{dy}}{{dx}}} \right) + 1 = 0$ is• $3$• $2$• $1$• not defined

Official Solution

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Discussion (0)

The degree of the differential equation
${\left( {\cfrac{{{d^2}y}}{{d{x^2}}}} \right)^3} + \left( {\cfrac{{dy}}{{dx}}} \right) + \sin \left( {\cfrac{{dy}}{{dx}}} \right) + 1 = 0$ is
• $3$
• $2$
• $1$
• not defined