$y'' + {(y')^2} + 2y = 0$
$y'' + {(y')^2} + 2y = 0$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
.: The highest order derivative is $y''$ and the
degree of its highest order is 1.
Therefore, the
given differential equation is of order 2 and degree 1.
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