$\int {\cfrac{{{{\sec }^2}x}}{{\cos e{c^2}x}}dx}$
$\int {\cfrac{{{{\sec }^2}x}}{{\cos e{c^2}x}}dx}$
Official Solution
VVidaara Team
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NCERT & Exemplar
: Let$I = \int {\cfrac{{{{\sec }^2}x}}{{\cos e{c^2}x}}dx} = \int {\cfrac{1}{{{{\cos }^2}x}} \cdot {{\sin }^2}xdx}$
$= \int {{{\tan }^2}xdx} = \int {\left( {{{\sec }^2}x - 1} \right)dx = \tan x - x + C}$
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