The anti derivative of $\left( {\sqrt x + \cfrac{1}{{\sqrt x }}} \right)$ equals

Option c is correct
Let $I = \int {\left( {\sqrt x + \cfrac{1}{{\sqrt x }}} \right)dx} = \int {\left( {{x^{1/2}} + {x^{ - 1/2}}} \right)dx}$

$= \cfrac{2}{3}{x^{3/2}} + 2{x^{1/2}} + C$