$\int {\left( {4{e^{3x}} + 1} \right)dx}$
$\int {\left( {4{e^{3x}} + 1} \right)dx}$
Official Solution
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NCERT & Exemplar
: Let $I = \int {\left( {4{e^{3x}} + 1} \right)dx} = \cfrac{{4{e^{3x}}}}{3} + x + C$
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