$\int {\cfrac{{{{\sin }^2}x - {{\cos }^2}x}}{{si{n^2}x{{\cos }^2}x}}dx}$ is equals to
$\int {\cfrac{{{{\sin }^2}x - {{\cos }^2}x}}{{si{n^2}x{{\cos }^2}x}}dx}$ is equals to
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Option a is correct
Let $I = \int {\cfrac{{{{\sin }^2}x - {{\cos }^2}x}}{{si{n^2}x{{\cos }^2}x}}dx}$
$= \int {\left( {{{\sec }^2}x - \cos e{c^2}x} \right)dx} = \tan x + \cot x + C$
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