$\int {\cfrac{{dx}}{{{x^2} + 2x + 2}}}$ equals
$\int {\cfrac{{dx}}{{{x^2} + 2x + 2}}}$ equals
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Option b is correct
Let $I = \int {\cfrac{{dx}}{{{x^2} + 2x + 2}}} = \int {\cfrac{{dx}}{{{{\left( {x + 1} \right)}^2} + 1}}} = {\tan ^{ - 1}}\left( {x + 1} \right) + C$
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