${e^x}\left( {\cfrac{1}{x} - \cfrac{1}{{{x^2}}}} \right)$
${e^x}\left( {\cfrac{1}{x} - \cfrac{1}{{{x^2}}}} \right)$
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Let $I = \int {{e^x}\left( {\cfrac{1}{x} - \cfrac{1}{{{x^2}}}} \right)dx} = \int {{e^x}\left( {\cfrac{1}{x} + \left( {\cfrac{d}{{dx}}\left( {\cfrac{1}{x}} \right)} \right)} \right)} dx$
$= \left[ {{e^x} \times \cfrac{1}{x} + C} \right]$
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