Integrals — Class 12 Maths Solution

Let $I = \int {{e^x}\left( {\cfrac{1}{x} - \cfrac{1}{{{x^2}}}} \right)dx} = \int {{e^x}\left( {\cfrac{1}{x} + \left( {\cfrac{d}{{dx}}\left( {\cfrac{1}{x}} \right)} \right)} \right)} dx$

$= \left[ {{e^x} \times \cfrac{1}{x} + C} \right]$