$\int {{e^x}\sec x\left( {1 + \tan x} \right)dx}$ equals
$\int {{e^x}\sec x\left( {1 + \tan x} \right)dx}$ equals
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Option b is correct
$\int {{e^x}\left( {\sec x + \sec x\tan \,x} \right)} dx = {e^x}\sec x + C$
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