$\int {\sqrt {{x^2} - 8x + 7} dx}$ is equal to
$\int {\sqrt {{x^2} - 8x + 7} dx}$ is equal to
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Option d is correct
Let $I = \int {\sqrt {{x^2} - 8x + 7} dx} = \int {\sqrt {{{\left( {x - 4} \right)}^2} - {3^2}} } dx$
$= \cfrac{{x - 4}}{2}\sqrt {{x^2} - 8x + 7} - \cfrac{9}{2}\log \left| {\left( {x - 4} \right) + \sqrt {{x^2} - 8x + 7} } \right| + C$
Community Answers (0)
Log in to post your own answer or join the discussion.
No comments yet — start the discussion.