class 12 maths inverse trigonometric functions

The value of ${\sin ^{ - 1}}\left[ {\cos \left( {\frac{{33\pi }}{5}} \right)} \right]$ is

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📘 Inverse Trigonometric Functions NCERT,Ex.2.3,Q.23,Page.37 MCQ 1 mark

The value of ${\sin ^{ - 1}}\left[ {\cos \left( {\frac{{33\pi }}{5}} \right)} \right]$ is

Official Solution

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We have,
${\sin ^{ - 1}}\left( {\cos \frac{{33\pi }}{5}} \right) = {\sin ^{ - 1}}\left[ {\cos \left( {6\pi + \frac{{3\pi }}{5}} \right)} \right] = {\sin ^{ - 1}}\left[ {\cos \left( {\frac{{3\pi }}{5}} \right)} \right]$

$= {\sin ^{ - 1}}\left[ {\cos \left( {\frac{\pi }{2} + \frac{\pi }{{10}}} \right)} \right] = {\sin ^{ - 1}}\left( { - \sin \frac{\pi }{{10}}} \right)$
$= - {\sin ^{ - 1}}\left( {\sin \frac{\pi }{{10}}} \right)$

$= - \frac{\pi }{{10}}$

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