class 12 maths inverse trigonometric functions

The value of $\sin \left[ {2{{\tan }^{ - 1}}(0.75)} \right]$ is

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📘 Inverse Trigonometric Functions NCERT,Ex.2.3,Q.27,Page.38 MCQ 1 mark

The value of $\sin \left[ {2{{\tan }^{ - 1}}(0.75)} \right]$ is

Official Solution

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We have, $\sin \left[ {2{{\tan }^{ - 1}}(0.75)} \right] = \sin \left( {2{{\tan }^{ - 1}}\frac{3}{4}} \right)$

$= \sin \left( {{{\sin }^{ - 1}}\frac{{2 \cdot \frac{3}{4}}}{{1 + \frac{9}{{16}}}}} \right) = \sin \left[ {{{\sin }^{ - 1}}\frac{{3/2}}{{25/16}}} \right]$

$= \sin \left[ {{{\sin }^{ - 1}}\left( {\frac{{48}}{{50}}} \right)} \right] = \sin \left[ {{{\sin }^{ - 1}}\left( {\frac{{24}}{{25}}} \right)} \right] = \frac{{24}}{{25}} = 0.96$

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