If ${\tan ^{ - 1}}x + {\tan ^{ - 1}}y = \frac{{4\pi }}{5}$, then ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y$ equals to
If ${\tan ^{ - 1}}x + {\tan ^{ - 1}}y = \frac{{4\pi }}{5}$, then ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y$ equals to
Official Solution
We have, ${\tan ^{ - 1}}x + {\tan ^{ - 1}}y = \frac{{4\pi }}{5}$
$\Rightarrow$ $\frac{\pi }{2} - {\cot ^{ - 1}}x + \frac{\pi }{2} - {\cot ^{ - 1}}y = \frac{{4\pi }}{5}$
$\Rightarrow$ $- \left( {{{\cot }^{ - 1}}x + {{\cot }^{ - 1}}y} \right) = \frac{{4\pi }}{5} - \pi$
$\Rightarrow$ ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y = - \left( { - \frac{\pi }{5}} \right)$
$\Rightarrow$ ${\cot ^{ - 1}}x + {\cot ^{ - 1}}y = \frac{\pi }{5}$
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