- 1 ( - x 2 ), ;|x| ; < a

Put x = asin we get : tan -1 ( acos ) = tan -1 (tan ) = = sin -1 ( a )

class 12 maths inverse trigonometric functions

${\tan ^{ - 1}}\left( {\frac{x}{{\sqrt {{a^2} - {x^2}} }}} \right),\;|x|\; < a$

VAVidaara Admin Asked 8d ago 0 views 0 answers

📘 Inverse Trigonometric Functions NCERT Ex. 2.2, Q. 9 , Page 48 SA

${\tan ^{ - 1}}\left( {\frac{x}{{\sqrt {{a^2} - {x^2}} }}} \right),\;|x|\; < a$

VVidaara Team ✓ Verified solution NCERT & Exemplar

Put x = $asin\theta$ we get :

$tan^{-1}( \frac{asin\theta}{acos\theta} )$

$= tan^{-1}(tan\theta) = \theta$

$= sin^{-1}(\frac{x}{a} )$

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