. Refer to question 13. Solve the linear programming problem and determine the maximum profit to the manufacturer.

Referring to Solution 13, We have the following conditions as per the question,
Maximise $Z = 100x + 170y$ subject to

$3x + 2y \le 3600,x + 4y \le 1800,x \ge 0,y \ge 0$

From the shaded feasible region it is clear that the coordinates of corner points are (0,0), (1200,0),(1080,180) and (0,450).

On solving $x + 4y = 1800$ and $3x + 2y = 3600$, we get $x = 1080$ and $y = 180$

Hence, the maximum profit to the manufacturer is 138600 .