Linear Programming — Class 12 Maths Solution

Referring to Solution 13, We have the following conditions as per the question,
Maximise $Z = 100x + 170y$ subject to

$3x + 2y \le 3600,x + 4y \le 1800,x \ge 0,y \ge 0$

From the shaded feasible region it is clear that the coordinates of corner points are (0,0), (1200,0),(1080,180) and (0,450).

On solving $x + 4y = 1800$ and $3x + 2y = 3600$, we get $x = 1080$ and $y = 180$

Hence, the maximum profit to the manufacturer is 138600 .