A flashlight has 8 batteries out of which 3 are dead. If two batteries are selected without replacement and tested, then probability that both are dead is
A flashlight has 8 batteries out of which 3 are dead. If two batteries are selected without replacement and tested, then probability that both are dead is
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Required probability $= {P_D} \cdot {P_D} = \frac{3}{8} \cdot \frac{2}{7} = \frac{3}{{28}}$
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