Given that E and F are events such that P(E) = 0.6,P(F) = 0.3 and P(E P) = 0.2 , find P(E|F) and P(F|E) .

.: P(E|F) = P(F) = 03 = 3 and P(F|E) = P(E) = 0.6 = 3

class 12 maths probability

Given that $E$ and F are events such that $P(E) = 0.6,P(F) = 0.3$ and $P(E \cap P) = 0.2$ , find $P(E|F)$ and $P(F|E)$ .

VAVidaara Admin Asked 8d ago 0 views 0 answers

📘 Probability NCERT,EX.13.1,Q.1,Page.538 SA

Given that $E$ and F are events such that $P(E) = 0.6,P(F) = 0.3$ and $P(E \cap P) = 0.2$ , find $P(E|F)$ and $P(F|E)$ .

VVidaara Team ✓ Verified solution NCERT & Exemplar

.: $P(E|F) = \cfrac{{P(E \cap F)}}{{P(F)}} = \cfrac{{0.2}}{{03}} = \cfrac{2}{3}$

and $P(F|E) = \cfrac{{P(F \cap E)}}{{P(E)}} = \cfrac{{0.2}}{{0.6}} = \cfrac{1}{3}$

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