If $P(A) = \cfrac{1}{2},P(B) = 0,$ then $P(A|B)$ is
(A) 0
(B) $\cfrac{1}{2}$
(C) not defined
(D) 1
If $P(A) = \cfrac{1}{2},P(B) = 0,$ then $P(A|B)$ is
(A) 0
(B) $\cfrac{1}{2}$
(C) not defined
(D) 1
Official Solution
VVidaara Team
✓ Verified solution
NCERT & Exemplar
Option C is correct
$P(A|B) = \cfrac{{P(A \cap B)}}{{P(B)}}$ ,
which is not defined as $P(B) = 0$
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