If $f:R \to R$ be the functions defined by $f(x) = {x^3} + 5$, then ${f^{ - 1}}(x)$ is

It is given that,, $f(x) = {x^3} + 5$

Let $y = {x^3} + 5 \Rightarrow {x^3} = y - 5$

$x = {(y - 5)^{\frac{1}{3}}} \Rightarrow f{(x)^{ - 1}} = {(x - 5)^{\frac{1}{3}}}$