If $f:N \to R$ be the function defined by
$f(x) = \frac{{2x - 1}}{2}$ and $g:Q \to R$ be
another function defined by $g(x) = x + 2$.
Then, $(gof)\frac{3}{2}$ is
If $f:N \to R$ be the function defined by
$f(x) = \frac{{2x - 1}}{2}$ and $g:Q \to R$ be
another function defined by $g(x) = x + 2$.
Then, $(gof)\frac{3}{2}$ is
Official Solution
VVidaara Team
✓ Verified solution
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It is given that,, $f(x) = \frac{{2x - 1}}{2}$ and $g(x) = x + 2$
$(gof)\frac{3}{2} = g\left[ {f\left( {\frac{3}{2}} \right)} \right] = g\left( {\frac{{2 \times \frac{3}{2} - 1}}{2}} \right)$
$= g(1) = 1 + 2 = 3$
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