Question
If $f:N \to R$ be the function defined by
$f(x) = \frac{{2x - 1}}{2}$ and $g:Q \to R$ be
another function defined by $g(x) = x + 2$.
Then, $(gof)\frac{3}{2}$ is
- (a) 1
- (b) 1
- (c) $\frac{7}{2}$
- (d) None of these ✓ Correct
If $f:N \to R$ be the function defined by
$f(x) = \frac{{2x - 1}}{2}$ and $g:Q \to R$ be
another function defined by $g(x) = x + 2$.
Then, $(gof)\frac{3}{2}$ is
It is given that,, $f(x) = \frac{{2x - 1}}{2}$ and $g(x) = x + 2$
$(gof)\frac{3}{2} = g\left[ {f\left( {\frac{3}{2}} \right)} \right] = g\left( {\frac{{2 \times \frac{3}{2} - 1}}{2}} \right)$
$= g(1) = 1 + 2 = 3$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Relations and Functions. Curated by Sachin Sharma. Free for all students.