class 12 maths three dimensional geometry

The distance of the plane $\overrightarrow {\rm{r}} \left( {\frac{2}{7}\widehat {\rm{i}} + \frac{3}{7}\widehat {\rm{j}} - \frac{6}{7}\widehat {\rm{k}}} \right) = 1$ from the origin is

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📘 Three Dimensional Geometry NCERT,Exemp.Q.31,Page.238 MCQ 1 mark

The distance of the plane $\overrightarrow {\rm{r}} \left( {\frac{2}{7}\widehat {\rm{i}} + \frac{3}{7}\widehat {\rm{j}} - \frac{6}{7}\widehat {\rm{k}}} \right) = 1$ from the origin is

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The distance of the plane $\overrightarrow {\rm{r}} \left( {\frac{2}{7}\widehat {\rm{i}} + \frac{3}{7}\widehat {\rm{j}} - \frac{6}{7}\widehat {\rm{k}}} \right) = 1$ from the origin is 1 .

[since, $\overrightarrow {\rm{r}} \cdot \overrightarrow {\rm{n}} = d$

is the form of above equation, where $d$ represents the distance of plane from the origin i.e., $d = 1]$

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