The distance of the plane $\overrightarrow {\rm{r}} \left( {\frac{2}{7}\widehat {\rm{i}} + \frac{3}{7}\widehat {\rm{j}} - \frac{6}{7}\widehat {\rm{k}}} \right) = 1$ from the origin is
The distance of the plane $\overrightarrow {\rm{r}} \left( {\frac{2}{7}\widehat {\rm{i}} + \frac{3}{7}\widehat {\rm{j}} - \frac{6}{7}\widehat {\rm{k}}} \right) = 1$ from the origin is 1 .
[since, $\overrightarrow {\rm{r}} \cdot \overrightarrow {\rm{n}} = d$
is the form of above equation, where $d$ represents the distance of plane from the origin i.e., $d = 1]$
NCERT & Exemplar solution for CBSE Class 12 Mathematics, Three Dimensional Geometry. Curated by Sachin Sharma. Free for all students.