JEE chemistry

Complete: C₆H₅N₂^+Cl^- reacts with: (a) CuCN (b) HBF₄ (c) H₃PO₂ + H₂O — JEE Chemistry

RBRitika Bose · 12 Asked 22d ago 1,254 views 1 answer

Complete: $C_6H_5N_2^+Cl^-$ reacts with:
(a) $CuCN$ (b) $HBF_4$ (c) $H_3PO_2 + H_2O$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 21d ago ▲ 12

(a) Sandmeyer reaction with CuCN:

$$C_6H_5N_2^+Cl^- + CuCN \rightarrow C_6H_5CN (benzonitrile) + N_2$$

(b) Balz–Schiemann reaction:

$$C_6H_5N_2^+Cl^- + HBF_4 \rightarrow C_6H_5N_2^+BF_4^- \xrightarrow{\Delta} C_6H_5F (fluorobenzene) + N_2 + BF_3$$

(c) Deamination (replacement by H):

$$C_6H_5N_2^+Cl^- + H_3PO_2 + H_2O \rightarrow C_6H_6 (benzene) + N_2 + HCl + H_3PO_3$$

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Discussion (4)

NA
Underrated solution. The way you set it up makes it almost obvious.
Nisha Agarwal · 21d ago
SJ
Thanks a ton, I was stuck on this exact problem for an hour.
Shruti Jain · 21d ago
AS
Why do we take the positive value only in the last step?
Arjun Sharma · 20d ago
E
Brilliant explanation, the substitution step is what I kept missing.
EthanWalker47 · 18d ago
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