[JEE Advanced 1982] Eight chairs are numbered $1$–$8$. Two women first choose chairs from $1$–$4$, then three men choose from the remaining chairs. The number of possible arrangements is
Eight chairs are numbered $1$–$8$. Two women first choose chairs from $1$–$4$, then three men choose from the remaining chairs. The number of possible arrangements is
(a) $\binom63\times\binom42$
(b) $^4P_2\times{}^6P_3$
(c) $\binom42+{}^4P_3$
(d) none of these
1 Answer
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· 1mo ago
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Correct answer: (b) $^4P_2\times{}^6P_3$
Women: $^4P_2$ from chairs $1$–$4$; men: $^6P_3$ from the remaining $6$ chairs. Product $^4P_2\times{}^6P_3$.
JEE Advanced 1982 · Permutations and Combinations — verified solution by the Vidaara Team.
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