[JEE Advanced 1978] Find all integers $x$ with $(5x-1)<(x+1)^2<(7x-3)$.
Find all integers $x$ with $(5x-1)<(x+1)^2<(7x-3)$.
1 Answer
VAVidaara Admin
✓ Vidaara Team
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· 1mo ago
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Answer: $x=3$.
Left: $(x+1)^2>5x-1\Rightarrow x<1$ or $x>2$. Right: $(x+1)^2<7x-3\Rightarrow1<x<4$. Intersection $2<x<4$, integer $x=3$.
JEE Advanced 1978 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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