Find all real x with x²-3x+2>0 and x²-2x-4 0.

Answer: x∈[1- 5,1)∪(2,1+ 5]. First gives x 2; second gives 1- 5≤ x 1+ 5. Intersection is [1- 5,1)∪(2,1+ 5]. JEE Advanced 1983 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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[JEE Advanced 1983] find all real x with x 2 3x 2 0 and x 2 2x

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Find all real $x$ with $x^2-3x+2>0$ and $x^2-2x-4\le0$.

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VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 2d ago ▲ 0

Answer: $x\in[1-\sqrt5,1)\cup(2,1+\sqrt5]$.

First gives $x<1$ or $x>2$; second gives $1-\sqrt5\le x\le1+\sqrt5$. Intersection is $[1-\sqrt5,1)\cup(2,1+\sqrt5]$.

JEE Advanced 1983 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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