Find all x for which 2x 2x²+5x+2 > 1 x+1.

Answer: x∈(-2,-1)∪ (- 23,- 12 ). The difference simplifies to (-(3x+2))/((2x+1)(x+2)(x+1))>0; a sign chart over -2,-1,- 23,- 12 gives (-2,-1)∪(- 23,- 12). JEE Advanced 1987 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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[JEE Advanced 1987] Find all $x$ for which $\dfrac{2x}{2x^2+5x+2}>\dfrac1{x+1}$.

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Find all $x$ for which $\dfrac{2x}{2x^2+5x+2}>\dfrac1{x+1}$.

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VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 0

Answer: $x\in(-2,-1)\cup\left(-\tfrac23,-\tfrac12\right)$.

The difference simplifies to $\frac{-(3x+2)}{(2x+1)(x+2)(x+1)}>0$; a sign chart over $-2,-1,-\frac23,-\frac12$ gives $(-2,-1)\cup(-\frac23,-\frac12)$.

JEE Advanced 1987 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.

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