Find the value of 4^log₂ 5 — JEE Mathematics
Find the value of $4^{\log_2 5}$.
1 Answer
NNabinThapa70
✓ Accepted
· 1mo ago
▲ 34
Rewrite the base 4 as $2^2$:
$$4^{\log_2 5} = (2^2)^{\log_2 5} = 2^{2\log_2 5}$$
Using the power rule of logarithms ($n\log b = \log b^n$):
$$2^{\log_2(5^2)} = 2^{\log_2 25}$$
Using the property $b^{\log_b a} = a$:
$$2^{\log_2 25} = 25$$
Answer: 25
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Discussion (2)
DM
What changes if the medium/conditions were different?
C
Adding for context: NCERT covers the base concept in the same chapter.