[JEE Advanced 2000] for 3x 2 px 3 0 with p 0 if one root is the
For $3x^2+px+3=0$ with $p>0$, if one root is the square of the other, then $p=$
(a) $\frac13$
(b) $1$
(c) $3$
(d) $\frac23$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
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Correct answer: (c) $3$
Roots $r,r^2$ with product $r^3=1$. Real $r=1$ gives $p=-6<0$ (rejected); complex $r=\omega$ gives $r+r^2=-1=-\frac p3\Rightarrow p=3$.
JEE Advanced 2000 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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