[JEE Advanced 1981] for every integer n 1 n 1 n n 1 2
For every integer $n>1$, $(n!)^{1/n}<\frac{n+1}2$.
1 Answer
VAVidaara Admin
✓ Vidaara Team
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· 2d ago
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Answer: True.
By AM–GM, $(n!)^{1/n}<\frac{1+2+\cdots+n}n=\frac{n+1}2$ (strict for $n>1$).
JEE Advanced 1981 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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