[JEE Main 2003] for x 0 the first negative term in the expansion of 1 x 27
For $x>0$, the first negative term in the expansion of $(1+x)^{27/5}$ is the
(a) 6th term
(b) 7th term
(c) 5th term
(d) 8th term
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (d) 8th term
The coefficient first turns negative when $k>\frac{27}5+1=6.4$, i.e. at $k=7$ — the 8th term.
JEE Main 2003 · Binomial Theorem — verified solution by the Vidaara Team.
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