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[JEE Advanced 2016] From $6$ girls and $4$ boys, a team of $4$ plus a captain (from the $4$) is chosen with at most one boy. The number of ways is

VAVidaara Admin Asked 1mo ago 1 views 1 answer
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From $6$ girls and $4$ boys, a team of $4$ plus a captain (from the $4$) is chosen with at most one boy. The number of ways is

(a) $380$
(b) $320$
(c) $260$
(d) $95$

1 Answer

VAVidaara Admin ✓ Vidaara Team ✓ Accepted · 1mo ago ▲ 0

Correct answer: (a) $380$

$0$ boys: $\binom64\cdot4=60$; $1$ boy: $\binom63\binom41\cdot4=320$. Total $380$.

JEE Advanced 2016 · Permutations and Combinations — verified solution by the Vidaara Team.

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