JEE chemistry

Glucose and fructose are both C₆H₁₂O₆ but differ in functional groups — JEE Chemistry

KKavyaSharma27 Asked 2mo ago 810 views 1 answer

Glucose and fructose are both $C_6H_{12}O_6$ but differ in functional groups. Explain why glucose gives a silver mirror test but fructose also does.

1 Answer

AAayushaRai25 ✓ Accepted · 1mo ago ▲ 36
  • Glucose is an aldohexose (contains –CHO aldehyde group) → reduces Tollens' reagent directly.

  • Fructose is a ketohexose (contains –CO– ketone group) → normally ketones don't reduce Tollens'. However, fructose is an $\alpha$-hydroxy ketone. In basic medium (Tollens'), it isomerises to glucose and mannose via enediol intermediate.

$$Fructose \xrightarrow{OH^-} Enediol \rightarrow Glucose + Mannose$$

$$Both give silver mirror test; fructose due to enolization in base$$

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Discussion (4)

AB
This finally made it click for me — thank you!
Aditi Banerjee · 1mo ago
VC
This is exactly the kind of step-by-step I needed. Respect.
Varun Choudhary · 1mo ago
C
Brilliant explanation, the substitution step is what I kept missing.
ChloeLefevre13 · 1mo ago
R
What changes if the medium/conditions were different?
RiteshBasnet93 · 1mo ago
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