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How many 4-digit numbers can be formed using digits 1 to 9 without repetition?

TSTushar Saxena · 10 Asked 13d ago 279 views 1 answer

I tried to solve this but got confused about whether to use permutation or combination. I get different answers depending on whether I use P(9,4) or C(9,4). Which is correct and why?

1 Answer

SJShruti Jain ✓ Accepted · 13d ago ▲ 6

Use PERMUTATION P(9,4) because the ORDER matters in a number. 1234 and 4321 are different 4-digit numbers. P(9,4) = 9!/(9-4)! = 9876 = 3024. Think of it as: 4 positions to fill. Position 1 (thousands): 9 choices. Position 2 (hundreds): 8 remaining choices. Position 3 (tens): 7 choices. Position 4 (units): 6 choices. Total = 9876 = 3024. Use combination C(9,4) only when order does NOT matter, like selecting a committee of 4 from 9 people. C(9,4) = 126 represents the number of ways to choose which 4 digits to use, without regard to their order.

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