[JEE Main 2006] if 0 x pi and cos x sin x 12 then tan x is
If $0<x<\pi$ and $\cos x+\sin x=\frac12$, then $\tan x$ is
(a) $\frac{1-\sqrt7}4$
(b) $\frac{4-\sqrt7}3$
(c) $-\frac{4+\sqrt7}3$
(d) $\frac{1+\sqrt7}4$
1 Answer
Correct answer: (c) $-\frac{4+\sqrt7}3$
Squaring: $\sin2x=-\frac34$; with $\cos x+\sin x=\frac12>0$ and $x$ obtuse, $\sin x-\cos x=\frac{\sqrt7}2$, giving $\tan x=-\frac{4+\sqrt7}3$.
JEE Main 2006 · Trigonometry — verified solution by the Vidaara Team.
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