[JEE Main 2005] If $1,\omega,\omega^2$ are the cube roots of unity, the roots of $(x-1)^3+8=0$ are

If $1,\omega,\omega^2$ are the cube roots of unity, the roots of $(x-1)^3+8=0$ are

(a) $-1,\,-1+2\omega,\,-1-2\omega^2$
(b) $-1,-1,-1$
(c) $-1,\,-1-2\omega,\,1-2\omega^2$
(d) $-1,\,1+2\omega,\,1+2\omega^2$