[JEE Main 2004] if 1 p is a root of x 2 px 1 p 0 then
If $(1-p)$ is a root of $x^2+px+(1-p)=0$, then the roots are
(a) $-1,2$
(b) $-1,1$
(c) $0,-1$
(d) $0,1$
1 Answer
VAVidaara Admin
✓ Vidaara Team
✓ Accepted
· 2d ago
▲ 0
Correct answer: (c) $0,-1$
Substituting $x=1-p$: $(1-p)(2)=0\Rightarrow p=1$; the equation becomes $x^2+x=0$ with roots $0,-1$.
JEE Main 2004 · Quadratic Equations and Inequations — verified solution by the Vidaara Team.
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